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13s^2-14s+1=0
a = 13; b = -14; c = +1;
Δ = b2-4ac
Δ = -142-4·13·1
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-12}{2*13}=\frac{2}{26} =1/13 $$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+12}{2*13}=\frac{26}{26} =1 $
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